Question 135519
What is your question? 

{{{x= -(log(3) + log(14))/(log(3) + log(4) - log(14)) }}} 

Are you asking how did they get that?
{{{4^x * 3^(x+1) = 14^(x-1)}}}
{{{x*log(4) + (x+1)log(3) = (x-1)log(14)}}}
{{{x*log(4) + x*log(3) + log(3) = x*log(14) - log(14)}}}
{{{x*log(4) + x*log(3) -x*log(14)= -log(3) - log(14)}}}
{{{x(log(4) + log(3) -log(14))= -log(3) - log(14)}}}
{{{x = -(log(3) + log(14))/(log(4) + log(3) -log(14))}}}