Question 135276
Use Descartes's rule of signs to discuss the possibilities for the roots of the equation. DO NOT solve the equation. 
4x^3-9x^2+6x+4=0 
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The number of changes of sign of f(x) is 2 so there are 2 or 0 positive Real roots.
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f(-x) = -4x^3-9x^2-6x+4
The number of changes of sign of f(-x) is one, so there are no negative
Real roots.
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You can find DesCartes's Rule of signs on-line by using Google or some other
search engine.
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Cheers,
Stan H.