Question 135288
Given: {{{3x^2-4x=2}}}
{{{3x^2-4x - 2 = 0}}}
Quadratic formula is {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

So, a = 3 , b = -4 , c = -2
 {{{x = (4 +- sqrt( (-4)^2-4*(3)*(-2) ))/(2*(3)) }}} 
 {{{x = (4 +- sqrt(16+24 ))/(6) }}} 
 {{{x = (4 +- sqrt(40))/(6) }}} 
 {{{x = (4 +- sqrt(4*10))/(6) }}} 
 {{{x = (4 +- 2*sqrt(10))/(6) }}} 
 {{{x = (2 +- sqrt(10))/(3) }}}