Question 135250
There are {{{6!/(2!(6-2)!)}}} ways to select 2 men from a group of 6 men and for each of these ways, there are {{{4!/(3!(4-3)!)}}} ways to select 3 women from a group of 4 women.


{{{6!/(2!(6-2)!)=6!/(2!*4!)=(6*5)/2=15}}}


{{{4!/(3!(4-3)!)=4!/(3!*1!)=24/6=4}}}


{{{15*4=60}}}