Question 135228
Solve by addition/subtraction:
1) {{{3x+2y  = 5}}}
2) {{{9x-2y = 15}}} Add equation 1) to equation 2)
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3) {{{12x = 20}}} Divide both sides by 12.
3a) {{{x = 20/12}}} Simplify.
{{{x = 5/3}}} Now substitute this for x in equation 1).
{{{3(5/3)+2y = 5}}}
{{{5+2y = 5}}} Subtract 5 from both sides.
{{{2y = 0}}} Divide both sides by 2.
{{{y = 0}}}
The solution is: ({{{5/3}}},{{{0}}})