Question 135220
1) (2+√3)÷√3  = [sqrt(3)*(2+sqrt(3)]/3 = (3+2sqrt(3))/3
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2) (√11+ 6) ÷ √27 = [sqrt(3)(sqrt(11) + 6)/9= [6sqrt(3)+sqrt(33))/9
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3) 2√7x²y÷ -3√18x³y = [(2sqrt(7)x^2y)/(-9sqrt(2)x^3y)][sqrt(2)/sqrt(2)]
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= [2sqrt(14)]/[-18x] = [-sqrt(14)]/[9x]
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4) 48√42x² ÷ 8 √6x = 6sqrt(7)x
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