Question 135161
taking log __ (1-x)log(4)=log(3)+(x)log(5)


distributing __ log(4)-(x)log(4)=log(3)+(x)log(5)


subtracting log(3) and adding (x)log(4) __ log(4)-log(3)=(x)log(5)+(x)log(4)


factoring __ log(4)-log(3)=(x)(log(5)+log(4))


dividing by log(5)+log(4) __ (log(4)-log(3))/(log(5)+log(4))=x



your answer seems right, but I can't follow your solution...