Question 135120
I'll assume you are not yet aware of complex numbers.

So, the domain of x for function {{{f(x)=sqrt(2x-3)}}}
Is any value that result in a real result. 

The square root of a negative number is not real. So the domain is any x where
{{{(2x-3)>= 0}}} 
{{{2x >= 3 }}}
{{{x >= 3/2}}}