Question 134976
On a coordinate plane P(0,4a) and Q(3a,0) are the endpoints of a diameter of a circle. What is the radius of the circle?
----------------------------------------------
Formula: distance = sqrt[(x-change)^2 + (y-change)^2]
d = sqrt[(3a)^2 + (4a)^2]
d = sqrt[25a^2]
d = 5a
==========
Cheers,
Stan H.