Question 134945

{{{3x^2+5x-8=0}}} Start with the given equation


{{{(3x+8)(x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{3x+8=0}}} or  {{{x-1=0}}} 


{{{x=-8/3}}} or  {{{x=1}}}    Now solve for x in each case



So our answer is 

 {{{x=-8/3}}} or  {{{x=1}}}