Question 134942

{{{x^4-13x^2+36=0}}} Start with the given equation


{{{(x^2-9)(x^2-4)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)



{{{(x+3)(x-3)(x-2)(x+2)=0}}} Factor {{{x^2-9}}} by use of the difference of squares to get {{{(x+3)(x-3)}}}. Factor {{{x^2-4}}} by use of the difference of squares to get {{{(x+2)(x-2)}}}


Now set each factor equal to zero:


{{{x+3=0}}}, {{{x-3=0}}}, {{{x-2=0}}} or {{{x+2=0}}}


Now solve for x for each factor:


{{{x=-3}}}, {{{x=3}}}, {{{x=2}}} or {{{x=-2}}}




So our answer is 


{{{x=-3}}}, {{{x=3}}}, {{{x=2}}} or {{{x=-2}}}