Question 134939

{{{8x^2=4x}}} Start with the given equation



{{{8x^2-4x=0}}}  Subtract 4x from both sides. 



{{{4x(2x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{4x=0}}} or  {{{2x-1=0}}} 


{{{x=0}}} or  {{{x=1/2}}}    Now solve for x in each case



So our answer is 

 {{{x=0}}} or  {{{x=1/2}}}