Question 134935
Given : {{{y=x^2}}}
{{{x^2+y^2=1}}}
{{{y+y^2=1}}}
{{{y^2+y-1=0}}}

Use the quadratic equation {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-1 +- sqrt( 1+4 ))/(2) }}}
{{{x = (-1 +- sqrt( 5 ))/(2) }}}