Question 134916
A standard baseball diamond is a square 90 feet on a side. Find the distance of a throw made from the catcher approximately 3 feet behind home plate in an attempt to throw out a runner trying to steal second base.

Pythagorean theorem:

a^2 + b^2 = c^2

We are looking for c + 3 feet (the distance where the catcher is situated behind home plate).

We must first find c.

(90)^2 + (90)^2 = c^2

16200 = c^2

Take square root of both sides.

127.2792206 = c

We can round 127.2792206 to the nearest ones place.

Doing this we get:

127 feet = c

However, the catcher is 3 feet BEHIND home plate.

We add 3 feet to 127 feet and we get 130 feet.

Did you follow?