Question 134884
Rule 1:  {{{n*log(b,x)}}} = {{{log(b,x^n)}}}


Rule 2:  {{{log(b,x[1])+log(b,x[2])=log(b,(x[1]x[2]))}}}


So:  {{{3log(x)+2log(y)-3log(z)=log(x^3)+log(y^2)+log(z^3)=log((x^3y^2z^3))}}}