Question 134819
Well for starters you need to find the slope of the line.  To find the slope you use the following formula:<br>

m = (y2-y1)/(x2-x1) where<br>

x1 = 6
y1 = -8
x2 = -2
y2 = -4<br>

so plugging into the formula you get<br>

m = (-4-(-8))/(-2-6)
m = (-4+8)/(-2-6)
m = 2/-8
m = -1/4<br>

now you can find the general from of the line by finding the y-intercept of that line(b in y = mx + b):<br>

y = mx + b
-4 = -1/4(-2) + b
-4 = 1/2 + b
-9/2 = b<br>

Now we can put this into slope-intercept form<br>

y = -1/4x - 9/2 <br>

From here you do a little math to get it into standard form. Standard form is ax + by = c where a, b, and c are all integers.<br>

y = -1/4x - 9/2 
4y = -x - 18
x + 4y = -18<br>

we found the y-intercept earlier to be -9/2.