Question 134791
Factor:
{{{18t^2-128}}} First, factor a 2.
{{{2(9t^2-64)}}} Now you can see that the paretheses contain the difference of two squares ({{{(3t)^2-(8)^2}}}) which is factored like this:
{{{A^2-B^2 = (A+B)(A-B)}}}, so...
{{{2(9t^2-64) = 2(3t+8)(3t-8)}}}