Question 134725
The easiest way to solve this is on a graph.  But i'm going to factor the equation to find ONLY the x-intercepts.....{{{x^2-x-12}}} This factors into {{{x-4=0}}} and {{{x+3=0}}} if you use the FOIL method {{{(x-4)(x-3)}}} you should get {{{x^2-x-12}}}.  The reason you set {{{x-4}}} and {{{x+3}}} to "0" is so you can solve for "x." x-4=0.....x=4 and x+3=0......x=-3.  The x-intercepts are (4,0) and (-3,0).  You should make a graph to find the y-intercept.  Since the highest power in the equation is "2" there should only be one y-intercept.  The vertex is the lowest point on the graph.{{{graph(300,200,-5,5,-15,15,x^2-x-12)}}}