Question 134752
If I understand the problem, it is
{{{(3y)^8 / (2zy)^2}}}
You can use the rule {{{(abc)^n = (a^n)*(b^n)*(c^n)}}}
{{{(3y)^8 / (2zy)^2 = ((3^8)*(y^8)) / ((2^2)*(z^2)*(y^2))}}}
{{{((3^8)*(y^8)) / ((2^2)*(z^2)*(y^2)) = (3^8)*(y^6) / 4z^2}}}
{{{(3^8)*(y*6) / 4z^2 = 6561y^6 / 4z^2}}}