<PRE><B>Question 134679</B>
LET THE SPED OF PLANE 1 = X 
LET THE SPED OF PLANE 2 = X+30
DISTANCE IN 40 MINUTES OF FLYING FOR PLANE 1=X(40/60)=(2/3)X
DISTANCE IN 40 MINUTES OF FLYING FOR PLANE 2=(X+30)(40/60)=(2/3)(X+30)
ADD THE TWO DISTANCES, 
(2/3)X + (2/3)(X+30)=260
2X/3+2X/3+20=260
4X/3=260-20
4X/3=240
X=240*3/4
X=180
THE SPED OF PLANE 1 = X =180
THE SPED OF PLANE 2 = X+30=180+30=210
SPEED UNIT MILES PER HOUR
OKAY




 
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