Question 134642
Try this:
{{{Log[9](x) = -(1/2)}}} Rewrite this in exponential form:{{{Log[b](y) = x}}} means {{{b^x = y}}}, so...
{{{Log[9](x) = -(1/2)}}} means {{{9^(-1/2) = x}}} Simplify. {{{1/sqrt(9) = x}}} or {{{1/3 = x}}}