Question 134670
log2(x-1)=1+log2(x-5) 
log2(x-1)-log2(x-5) = 1
log2[(x-1)/(x-5)] = 1
(x-1)/(x-5) = 2^1
x-1 = 2(x-5)
x-1 = 2x-10
x = 9
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Cheers,
Stan H.