Question 134587
Given: {{{(sqrt(2) + sqrt(3))(sqrt(3) + sqrt(2))}}}
{{{(sqrt(2)*sqrt(3) + sqrt(2)*sqrt(2) + sqrt(3)*sqrt(3) + sqrt(3)*sqrt(2))}}}  This is the way you distribute using 'plain old numbers'

Now, recognize that the sqrt of a number squared is just the number

{{{sqrt(2)sqrt(3) + 2 + 3 + sqrt(2)sqrt(3)}}}
{{{ 5 + 2sqrt(2)sqrt(3)}}}
{{{ 5 + 2*sqrt(6)}}}