Question 134457
Given: {{{x + 2y=2}}}
{{{1/2x + 1/3y=1}}}

Multiply the second equation by 2
{{{x + 2/3y = 2)}}}

Subtract this equation from the first one:
{{{x + 2y=2}}}
{{{x + 2/3y = 2)}}}
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{{{ (4/3)y = 0}}}
y = 0
Sub into the first equation
{{{x + 2y=2}}}
{{{x + 2(0) = 2}}}
x = 2

Check your answer using the second equation
Does {{{(1/2)(x) + (1/3)(0) = 1 }}}??/ check!