Question 134443
Are you sure that the question is {{{y=(3/5)x+7/10}}}?



{{{y=(3/5)x+7/10}}} Start with the given equation



{{{y-(3/5)x=7/10}}} Subtract (3/5)x from both sides 



{{{-(3/5)x+y=7/10}}} Rearrange the terms



{{{10(-(3/cross(5))x+y)=10(7/cross(10))}}} Multiply both sides by the LCD 10 to clear the fractions



{{{-6*x+10*y=7}}} Distribute and multiply




Now the equation is in standard form {{{Ax+By=C}}} where {{{A=-6}}}, {{{B=10}}} and {{{C=7}}}