Question 134423
{{{(8)/(21w) + (2)/(9w) }}} Start with the given expression



The LCM of {{{21w}}} and {{{9w}}} is {{{63w}}}. So we need to get each denominator to {{{63w}}}




{{{(3/3)((8)/(21w)) + (2)/(9w) }}} Multiply the first fraction by {{{3/3}}}



{{{(24)/(63w) + (2)/(9w) }}} Multiply



{{{(24)/(63w) + (7/7)((2)/(9w)) }}} Multiply the second fraction by {{{7/7}}}



{{{(24)/(63w) + (14)/(63w) }}} Multiply



{{{(24+14)/(63w) }}} Combine the fractions



{{{(38)/(63w) }}} Add




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Answer:



So {{{(8)/(21w) + (2)/(9w) }}} simplifies to {{{(38)/(63w) }}}



In other words, {{{(8)/(21w) + (2)/(9w)=(38)/(63w) }}}