Question 134409
Given: {{{e^(x - 2) = 15e^(-x)}}}
Take the natural log of both sides
{{{ln(e^(x-2)) = ln(15e^(-x)) }}}
{{{(x-2) = ln(15) + ln(e^(-x)) }}}
{{{(x-2) = ln(15) -x) }}}
{{{2x = 2.708 + 2 }}}
{{{x = 2.354 }}}

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