Question 134366
Let b=Bonita's time working alone, b+2=Pamela's time working alone.
Bonita can do 1/b of the job in 1 hr.
Pamela can do 1/(b+2) of the job in 1 hr.
Together they do 1/8 of the job in 1 hr.
1/b + 1/(b+2) = 1/8 LCD=8b(b+2)
8(b+2)+8b=b(b+2) multiply each side by the LCD to eliminate fractions.
8b+16+8b=b^2+2b
b^2+2b-8b-16-8b=0
b^2-14b-16=0
b=15.06 hrs.
b+2=17.06 hrs.
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Ed
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*[invoke solve_quadratic_equation 1, -14, -16]