Question 134342

{{{(1210b^4v^5)/(1100v^2b)}}} Start with the given expression.




{{{b^(4-1)v^(5-2)}}} Remember when you divide monomials, you subtract their corresponding exponents. For instance {{{x^2/x^3=x^(2-3)=x^-1}}}



{{{(11/10)b^3v^3}}} Simplify.  Remember to reduce the coefficients (which are numbers in front of the variables) to get {{{1210/1100=11/10}}}.




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Answer:


So {{{(1210v^5b^4)/(1100v^2b)}}} simplifies to {{{(11/10)b^3v^3}}}.


In other words, {{{(1210v^5b^4)/(1100v^2b)=(11/10)b^3v^3}}} where {{{b<>0}}} or {{{v<>0}}}