Question 134327
{{{-3x > 0}}} Start with the first inequality



{{{-3(-4) > 0}}} Plug in {{{x=-4}}}



{{{12 > 0}}} Multiply



Since this inequality is true, {{{x=-4}}} works for the first inequality.



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{{{3x-4 < 11}}} Start with the first inequality



{{{3(-4)-4 < 11}}} Plug in {{{x=-4}}}



{{{-12-4 <11}}} Multiply



{{{-16 <11}}} Subtract


Since this inequality is true, {{{x=-4}}} works for the second inequality.




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Conclusion:


Since {{{x=-4}}} satisfies both inequalities, this means that {{{x=-4}}} is in the solution interval.