Question 134281


Let's denote the first point (-5,3) as *[Tex \Large \left(x_{1},y_{1}\right)]. In other words, *[Tex \LARGE x_{1}=-5] and *[Tex \LARGE y_{1}=3]


Now let's denote the second point (5,-2) as *[Tex \Large \left(x_{2},y_{2}\right)]. In other words, *[Tex \Large x_{2}=5] and *[Tex \Large y_{2}=-2]




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{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula


{{{m=(-2-3)/(5--5)}}} Plug in {{{y[2]=-2}}},{{{y[1]=3}}},{{{x[2]=5}}},{{{x[1]=-5}}}



{{{m=-5/10}}} Subtract the terms in the numerator {{{-2-3}}} to get {{{-5}}}.  Subtract the terms in the denominator {{{5--5}}} to get {{{10}}}

  

{{{m=-1/2}}} Reduce


  

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Answer:


So the slope of the line through the points (-5,3) and (5,-2) is {{{m=-1/2}}}