Question 134273
{{{x+3y=12}}}

{{{ 3y=-x+12}}}

{{{y=-x/3+12/3}}}

{{{ y=-(1/3)x+4}}}

If {{{x=0}}}, then {{{y=4}}}….{{{y-intercept}}}….


*[invoke Plot_a_graph_of_functions "-(1/3)x+4", -10, 20, -10, 20]