Question 134213
A car is traveling on a road that is perpendicular to a railroad track. When the
 car is 30 meters from the crossing, the cars new collision detector warns the
 driver that there is a train 50 meters from the car heading toward the same
 crossing. How far is the train from the crossing?
:
This situation is in the form of a right triangle where one leg is dist to the
crossing, given as 30 meters. The distance from the train to the car is the
hypotenuse, given as 50 meters.  We want to find the 2nd leg of the triangle (b)
:
30^2 + b^2 = 50^2
900 + b^2 = 2500
b^2 = 2500 - 900
b^2 = 1600
b = {{{sqrt(1600)}}}
b = 40 meters
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