Question 134026
First we need to simplify these functions as much as possible.<br>

4x^2-10 = 2(2x^2-5)
x+3y = x+3y
2x^2-18y^2 = 2(x^2-9y)^2 = 2(x-3y)(x+3y)
6x^2-15 = 3(2x^2-5)<br>

so our problem becomes<br>

{{{((2(2x^2-5))/(x+3y)) * ((2(x-3y)(x+3y)) / (3(2x^2-5)))}}}<br>

now we can cancel some stuff off.<br>

{{{ 2 * ((2(x-3y))/3)}}}<br>

now multiplying out you get {{{(4(x-3y))/3}}} or {{{(4x-12y)/3}}}