<PRE><B>Question 134244</B>
Since one of the equations has a variable solved for already, lets use substitution.&lt;br&gt;

The steps in substitution are as follows:&lt;br&gt;

1) Solve one of the equations for a variable.
2) Plug in the value of that variable into the other equation and solve for the one variable left.
3) Plug that value into 1 and solve for the first variable.&lt;br&gt;

Since step one has already been done for us we can just jump to step to.&lt;br&gt;

2y - x = 3
 x = 3y - 5&lt;br&gt;

Plugging x = 3y-5 into the top equation you get:&lt;br&gt;

2y -(3y-5) = 3 &lt;br&gt;

now we just solve for y&lt;br&gt;

2y -(3y-5) = 3
2y - 3y + 5 = 3
-y + 5 = 3
-y = -2
y = 2&lt;br&gt;

Now we move on to step 3.  Plugging the value y = 2 into the second equation we get:&lt;br&gt;

x = 3(2)-5
x = 6 - 5
x = 1&lt;br&gt;

now we are done, our solution is (1,2) or x = 1 and y =2 depending on what form we want to leave it in.</PRE>