Question 134222
Let's graph the first equation {{{y=x^2}}}


{{{graph( 500, 500, -10, 10, -10, 10, x^2) }}}



Now let's add the graph of {{{y=(x-2)^2+3}}}


{{{graph( 500, 500, -10, 10, -10, 10, x^2,(x-2)^2+3) }}} Graph of {{{y=x^2}}} (red) and {{{y=(x-2)^2+3}}} (green)



Notice how the green graph, which is the equation {{{y=(x-2)^2+3}}}, is simply the same as the original graph, but has been shifted 2 units to the right and 3 units up. 



Note: The 2 unit shift to the right corresponds to the 2 in {{{(x-highlight(2))^2+3}}} and the 3 unit shift up corresponds to the 3 in {{{(x-2)^2+highlight(3)}}}