Question 134139
Apparently you are using degree measurements, so the complement of an angle that measures {{{alpha}}} degrees is {{{90-alpha}}} and the supplement is {{{180-alpha}}}


Ten times the complement ({{{10(90-alpha)}}})
Three times the supplement ({{{3(180-alpha)}}})
Exceeds by 318: +318,  so:


{{{10(90-alpha)=3(180-alpha)+318}}}  (ten times the complement is the bigger number so you have to add the 318 to the smaller number to make them equal)


{{{900-10alpha=540-3alpha+318}}}


{{{-10alpha+3alpha=540+318-900}}}


{{{-7alpha=-42}}}


{{{alpha = 6}}}


Check:
{{{90-6=84}}}
{{{10*84=840}}}

{{{180-6=174}}}
{{{3*174=522}}}


{{{840-522=318}}}