Question 134016
Solve for x:
{{{(3x-2)^2 = -9}}} Take the square root of both sides.
{{{3x-2 = sqrt(-9)}}} or {{{3x-2 = -sqrt(-9)}}}Add 2 to both sides.
{{{3x = 2+-3*sqrt(-9)}}}Divide both sides by 3.
{{{x = (2/3)+-sqrt(-1)}}} which can be written as:
{{{x = (2/3)+-i}}}