Question 133896

Let x=amount of water that needs to be added

Now we know that the pure acid in the water (0) plus the pure acid in the 60% solution (0.60*300) has to equal the amount of pure acid in the final mixture (0.45(300+x))

So our equation to solve is:

0.60*300=0.45(300+x) simplify
180=135+0.45x  subtract 135 from each side
180-135=0.45x
0.45x=45  divide both sides by 0.45

x=100ml------------------amount of water that needs to be added

CK

0.60*300=0.45*400
180=180


Hope this helps---ptaylor