Question 133893
Log([2-5x]/[2x+16]) = 0
If log a = k, then a =e^k

Hence (2-5x)/(2x+16) =e^0 =1

2-5x = 2x+16 ==>

-5x-2x = 16-2 = 14==>

-7x=14==>

x = 14/2 = -2