Question 133834
Let {{{f(x)=y=-2x^2}}} and let {{{g(x)=-4x^2}}}, since {{{g(x)=2*f(x)}}}, we can see that for every x except {{{x=0}}}, the magnitude of the value of {{{g(x)}}} will be twice that of the magnitude of {{{f(x)}}}.  {{{x=0}}} is excluded because {{{g(0)=f(0)}}}


Since the lead coefficient in each function is less than zero, the parabolas will be concave down, but {{{g(x)}}} will make a steeper but narrower hill.



The green graph is {{{g(x)}}}
{{{drawing(600,600,-6,6,-10,2,
grid(1),
graph(600,600,-6,6,-10,2,-2x^2,-4x^2)
)}}}