Question 133802
this equation is in "vertex" form __ y=a(x-h)^2+k __ where (h,k) is the vertex
__ the axis (of symmetry) passes through the vertex and has the equation x=h


vertex __ (-4,0)


axis __ x=-4


x can be any value so the domain is all real numbers


because of the square function, y can't be less than 0; so the range is all real numbers >= 0