Question 133759
Solve for x:
{{{1+(2/x) = 3/x^2}}} Multiply both sides by {{{x^2}}}
{{{x^2+(2x^2/x) = 3}}} Simplify.
{{{x^2+2x = 3}}} Subtract 3 from both sides.
{{{x^2+2x-3 = 0}}} Solve the quadratic equation by factoring.
{{{(x+3)(x-1) = 0}}} Apply the zero products rule.
{{{x+3 = 0}}} or {{{x-1 = 0}}}, so...
{{{x = -3}}} or {{{x = 1}}}