<PRE><B>Question 133702</B>
Suppose an outfielder catches the ball on the third base line about 40 feet behind third base. About how far would the outfielder have to throw the ball to first base?
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Draw the picture.
Distance between successive bases is 60 ft.
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Use Pythagoras to solve:
distance^2 = 100^2 + 60^2
distance^2 = 13600
disance = 116.62 ft.
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Cheers,
Stan H.</PRE>