Question 133697


{{{2x^2-7x-15=0}}} Start with the given equation


{{{(x-5)(2x+3)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x-5=0}}} or  {{{2x+3=0}}} 


{{{x=5}}} or  {{{x=-3/2}}}    Now solve for x in each case



So our answer is 

 {{{x=5}}} or  {{{x=-3/2}}}