Question 133698


{{{-2x^2-5x+12=0}}} Start with the given equation


{{{-(x+4)(2x-3)=0}}} Factor the left side



Now set each factor equal to zero:

{{{x+4=0}}} or  {{{2x-3=0}}} 


{{{x=-4}}} or  {{{x=3/2}}}    Now solve for x in each case



So our solutions are


 {{{x=-4}}} or  {{{x=3/2}}}