Question 133699
{{{3x^2+2x+3=4}}} Start with the given equation



{{{3x^2+2x+3-4=0}}}  Subtract 4 from both sides. 



{{{3x^2+2x-1=0}}} Combine like terms




{{{(x+1)(3x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{x+1=0}}} or  {{{3x-1=0}}} 


{{{x=-1}}} or  {{{x=1/3}}}    Now solve for x in each case



So our solutions are


 {{{x=-1}}} or  {{{x=1/3}}}