Question 133703
{{{8x=3x^2+5}}} Start with the given equation



{{{0=3x^2+5-8x}}}  Subtract 8x from both sides. 



{{{0=3x^2-8x+5}}} Rearrange the terms




{{{0=(3x-5)(x-1)}}} Factor the right side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{3x-5=0}}} or  {{{x-1=0}}} 


{{{x=5/3}}} or  {{{x=1}}}    Now solve for x in each case



So our solutions are


 {{{x=5/3}}} or  {{{x=1}}}