Question 133538
I think the problem is aksing for (f(g(x)) at the value x =1.

What you need to do is take the function g(x) and use that as the independent variable in f(x). As follows:
{{{f(x) = x+1}}}
{{{g(x) = 6/(x+1) }}}

Now put the value of g(x) as the independent variable in f(x):
{{{f(g(x)) = (6/(x+1)) + 1 }}}
Now you can either solve for f(g(x)) and then sub in 1, or just sub in one and solve. Let's sub in 1:

{{{f(g(1)) = (6/(1+1)) + 1 }}}
{{{f(g(1)) = (6/2) + 1 }}}
{{{f(g(1)) = 3 + 1 }}}
{{{f(g(x)) = 4 }}}

For your info, generally the function f(g(x)) is written as (fog(x))