Question 133617
(1-2i)x+2-3i=5-4i+2x
(1-2i)x-2x = 5-4i-2+3i
x[1-2i-2] = 3-i
x = (3-i)/(-1-2i)
Rationalizing the denominator you get:
x = [(3-i)(-1+2i)]/(1+4)
x = [-3+2-5i]/5
x = -(1+5i)/5
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Cheers,
Stan H.